Abhay's Math Page

Abhay's Math

Solution of the previous question

					2ab = 2a + 3b + 5


					2ab - 2a  = 3b + 5


					2a (b - 1) = 3(b - 1 + 1) + 5


					2a (b - 1) = 3(b - 1) + 3*1 + 5


					(2a - 3) (b - 1) = 8

Put (2a - 3) as 1,-1,2,-2,4,-4,8,-8 and corresponding values in (b - 1). Except for (2a - 3) = 1 and -1 you get a as a non integer. Reject that solution.

So 2a - 3 = 1 and b - 1 = 8, => a = 2 and b = 9 OR use 2a - 3 = -1 and b - 1 = -8, => a = 1 and b = -7.

Solution Set = { (2,9) , (1,-7) }