Abhay's Math Page

Abhay's Math

Solution set = { (2,3) , (3,2) , (0,-1) , (-1,0) }

Did you get them all ?

Now the proper method :

					ab = a + b + 1


					ab - b = a + 1


					b (a - 1) = a + 1


					b (a - 1) = (a - 1) + 1 + 1


					(a - 1) (b - 1) = 2

Pretty similar to the previous one ?

Put (a - 1) and (b - 1) as 1,-1,2,-2 i.e the factors of 2 and you get the solutions.